Watch Video on Graphing Linear Inequalities – Algebra Help
Access full lesson containing this video at: http://www.yourteacher.com/algebra1/graphinglinearinequalities.php Students learn to graph inequalities in two variables. For example, to graph y is less than x + 2, the first step is to graph the boundary line y = x + 2, using the chart method from lesson 4B. Note that greater than or less than means that the boundary line will be dotted, and greater than or equal to or less than or equal to means that the boundary line will be solid. To determine which side of the boundary line to shade, substitute a test point, such as (0, 0), into the original inequality, y is less than x + 2. Since (0) is less than (0) + 2, or 0 is less than 2, is a true statement, the side of the line that contains the point (0, 0) is shaded.
Duration : 0:4:7
[youtube 0VVQYOMRlkQ]
Tags: graph, Graphing, in, Inequalities, inequality, Linear, math, Two, Variables
November 13th, 2009 at 2:22 am
@Trogdor1597 It’s …
@Trogdor1597 It’s always 1,0,-1 because they’re easiest to graph if you used bigger numbers you’d have to create a graph of a larger scale.
November 13th, 2009 at 2:22 am
ursosexy luvin u …
ursosexy luvin u brah
November 13th, 2009 at 2:22 am
Umm… im just …
Umm… im just wondering but how did you do on that test??
November 13th, 2009 at 2:22 am
So is it always …
So is it always going to be 1 0 and -1????
November 13th, 2009 at 2:22 am
thx Your the BEST!! …
)
thx Your the BEST!!
i really apreciate it!!
November 13th, 2009 at 2:22 am
thx a lot!!!
)) …
))
thx a lot!!!
im really thankfull
November 13th, 2009 at 2:22 am
man i wish you were …
man i wish you were my teacher!
my teacher sucks!
November 13th, 2009 at 2:22 am
how would you do a …
how would you do a problem like y>=9/4x + 5
more simpler i need help on fractions
November 13th, 2009 at 2:22 am
your a god
your a god
November 13th, 2009 at 2:22 am
this helped alot!
this helped alot!
November 13th, 2009 at 2:22 am
lol like that …
lol like that comment. useless text book (not to mention teacher)
November 13th, 2009 at 2:22 am
dude, you saved my …
dude, you saved my ass, yet again, from an almost useless text book (not to mention teacher). Thanks so much!!!!
November 13th, 2009 at 2:22 am
what this mad me …
what this mad me mor confused 0,0
November 13th, 2009 at 2:22 am
I’m still confused …
I’m still confused at the last couple of steps. =/
November 13th, 2009 at 2:22 am
ok if you plug in …
ok if you plug in the point (0,0) into the graph with the innequality already drawn, the 0,0 will work beacuse its on the side thats been told. like the guy said 0 is grater than -3, its not asking you for the absolute value wich then would be 3 only. but that gets in the way of algebra and takes you into trigonometry and you dont want that
November 13th, 2009 at 2:22 am
To figure out on …
To figure out on what side of the boundary line the actual graph of y>-4x-3 is, you have to sub in a point (it can be any point that is not on the boudary). The easiest point to sub in is (o,o) where x=o and y=0 this is why he chose that point. After subbing, we can see that at point (0,0) the inequality is possible and thus it exists on the side of the boudary line where (0,0) is. I hope that helps
November 13th, 2009 at 2:22 am
it was just the …
it was just the test point he chose, since it fell on the upper right-hand side of the boundry line. then you use it to plug it in the original inequality, and if in the end the statement is true, that means that whole side is part of the solution. If you still don’t get it, use the point (1,1), or any other point on the other side so you can plug it in and see for yourself.
hope that helps
November 13th, 2009 at 2:22 am
hey i dont …
hey i dont understand the 0,0 thing
thanks to anyone that can help
November 13th, 2009 at 2:22 am
lol
lol
November 13th, 2009 at 2:22 am
I LOVE YOU!!! (no …
I LOVE YOU!!! (no gayness intended)
November 13th, 2009 at 2:22 am
awesome teacher
awesome teacher
November 13th, 2009 at 2:22 am
saved my life
saved my life
November 13th, 2009 at 2:22 am
yeah…but i …
yeah…but i thought the line is only dotted if the linear inequality is false. if it is true, then it is solid…???
November 13th, 2009 at 2:22 am
This guy is a robot …
This guy is a robot… thanks for the explanation.
November 13th, 2009 at 2:22 am
hmm… So YouTube …
hmm… So YouTube can be useful…